用简便方法怎么计算
(2+0.48+0.82)x(0.48+0.82+0.56)-(2+0.48+0.82+0.56)x(0.48+0.82)...
(2+0.48+0.82)x(0.48+0.82+0.56)-(2+0.48+0.82+0.56)x(0.48+0.82)
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原式=【2+0.48+0.82]*[0.48+0.82]+[2+0.48+0.82]*0.56-{[2+0.48+0.82]*[0.48+0.82]+0.56*[0.48+0.82]} =【2+0.48+0.82]*[0.48+0.82]-[2+0.48+0.82]*[0.48+0.82]+[2+0.48+0.82]*0.56-0.56*[0.48+0.82] =2*0.56=1.12
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(2+0.48+0.82)x(0.48+0.82+0.56)-(2+0.48+0.82+0.56)x(0.48+0.82)
=(2+0.48+0.82)x(0.48+0.82)+(2+0.48+0.82)x0.56-(2+0.48+0.82+0.56)x(0.48+0.82)
=(2+0.48+0.82)x(0.48+0.82)+(2+0.48+0.82)x0.56-(2+0.48+0.82)x(0.48+0.82)-0.56x(0.48+0.82)
=(2+0.48+0.82)x0.56-0.56x(0.48+0.82)
=(2+0.48+0.82)x0.56-(0.48+0.82)x0.56
=2x0.56
=1.12
=(2+0.48+0.82)x(0.48+0.82)+(2+0.48+0.82)x0.56-(2+0.48+0.82+0.56)x(0.48+0.82)
=(2+0.48+0.82)x(0.48+0.82)+(2+0.48+0.82)x0.56-(2+0.48+0.82)x(0.48+0.82)-0.56x(0.48+0.82)
=(2+0.48+0.82)x0.56-0.56x(0.48+0.82)
=(2+0.48+0.82)x0.56-(0.48+0.82)x0.56
=2x0.56
=1.12
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原式
= [(2+0.48+0.82)x(0.48+0.82)+(2+0.48+0.82)x0.56]-[(2+0.48+0.82)x(0.48+0.82)+0.56x(0.48+0.82)]
=
0.56x2=1.12
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= [(2+0.48+0.82)x(0.48+0.82)+(2+0.48+0.82)x0.56]-[(2+0.48+0.82)x(0.48+0.82)+0.56x(0.48+0.82)]
=
0.56x2=1.12
有什么问题楼主可提问，请采纳
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设0.48+0.82=a
∴原式可化为
(2+a)(a+0.56)-(2+a+0.56)a
=a²+2a+0.56a+1.12-a²-2a-0.56a
=1.12
∴原式可化为
(2+a)(a+0.56)-(2+a+0.56)a
=a²+2a+0.56a+1.12-a²-2a-0.56a
=1.12
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