Question

两道数学题求过程 第一道答案x^2/x+2y 第二道x²-y²

第二道我想出来了- - 求解第一道。。

Answer 1

第一题：
原式= （x+2y）+ 4x^2 y/ (4y^2-x^2) +4y^2 (x+2y)/ (x^2-4y^2)
=（x+2y）+[- 4x^2 y +4y^2 (x+2y)] / (x^2-4y^2)
=（x+2y）+[- 4x^2 y +4y^2 (x+2y)] / (x^2-4y^2)
= [(x+2y)（x^2-4y^2)+(- 4x^2 y +4xy^2 +8y^2) ]/(x^2-4y^2)
= [(x^3-4xy^2+2yx^2-8y^3)+(- 4x^2 y +4xy^2 +8y^2) ]/(x^2-4y^2)
=[(x^3+2yx^2)+(- 4x^2 y ) ]/(x^2-4y^2)
=(x^3-2yx^2)/(x^2-4y^2)
=x^2(x-2y)/(x^2-4y^2)
=x^2/(x+2y)

Answer 2

x+2y+ 4x^2y/(4y^2-x^2) + 4y^2/(x-2y)
= x+2y+ 4x^2y/(2y-x)(2y+x)+ 4y^2/(x-2y)
= x+2y- 4x^2y/(x-2y)(x+2y)+ 4y^2/(x-2y)
= [ x(x-2y)(x+2y)+ 2y(x-2y)(x+2y)- 4x^2y+ 4y^2(x-2y) ] /(x-2y)(x+2y)
= [ x(4y^2-x^2)+2y(4y^2-x^2)- 4x^2y+4xy^2-8y^3 ] /(x-2y)(x+2y)
= ( 4xy^2 - x^3 + 8y^3 -2x^2y -4x^2y + 4xy^2-8y^3 )/(x-2y)(x+2y)
= ( 8xy^2 - x^3 - 6x^2y ) /(x-2y)(x+2y)
= 2x(4y^2 -x^2 - 3xy) /(x-2y)(x+2y)
= 2x(-x^2- 3xy+4y^2 ) /(x-2y)(x+2y)
= - 2x(x^2+ 3xy-4y^2 ) /(x-2y)(x+2y)
= - 2x(x+4y)(x-y) / (x-2y)(x+2y)

Answer 3

是化简还是因式分解，第一道看不懂，可以换一张吗