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1、(1)2b/a;(2)(x+y)xy;(3)x(x+y)/(x+y)²=x/(x+y);(4)(x+y)(x-y)/(x-y)²=(x+y)/(x-y).
2、(1)2c/bd=(2c)·(4b)/(4b²d)=8bc/(4b²d);
3ac/(4b²)=3ac·d/(4b²d)=3acd/(4b²d)
(2)2xy/(x+y)²=2xy(x-y)/[(x+y)²(x-y)]
x/(x²-y²)=x/[(x-y)(x+y)]=x(x+y)/[(x-y)(x+y)²]
2、(1)2c/bd=(2c)·(4b)/(4b²d)=8bc/(4b²d);
3ac/(4b²)=3ac·d/(4b²d)=3acd/(4b²d)
(2)2xy/(x+y)²=2xy(x-y)/[(x+y)²(x-y)]
x/(x²-y²)=x/[(x-y)(x+y)]=x(x+y)/[(x-y)(x+y)²]
来自:求助得到的回答
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