
有一种24点的游戏,用3,4,13,6计算得到24,一个数只能用一次,可以加括号?
3个回答
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1: (3 + 13) ÷ 4 × 6
2: ((3 + 13) ÷ 4) × 6
3: (3 + 13) ÷ (4 ÷ 6)
4: (3 + 13) × 6 ÷ 4
5: ((3 + 13) × 6) ÷ 4
6: (3 + 13) × (6 ÷ 4)
7: (13 + 3) ÷ 4 × 6
8: ((13 + 3) ÷ 4) × 6
9: (13 + 3) ÷ (4 ÷ 6)
10: (13 + 3) × 6 ÷ 4
11: ((13 + 3) × 6) ÷ 4
12: (13 + 3) × (6 ÷ 4)
13: (6 × (3 + 13)) ÷ 4
14: 6 × (3 + 13) ÷ 4
15: 6 × ((3 + 13) ÷ 4)
16: 6 ÷ 4 ×(3 + 13)
17: (6 ÷ 4) × (3 + 13)
18: 6 ÷ (4 ÷ (3 + 13))
19: 6 ÷ 4 ×(13 + 3)
20: (6 ÷ 4) × (13 + 3)
21: 6 ÷ (4 ÷ (13 + 3))
22: (6 × (13 + 3)) ÷ 4
23: 6 × (13 + 3) ÷ 4
24: 6 × ((13 + 3) ÷ 4)
25: 6 ÷ (13 ÷ 4 - 3)
26: 6 ÷ ((13 ÷ 4) - 3)
2: ((3 + 13) ÷ 4) × 6
3: (3 + 13) ÷ (4 ÷ 6)
4: (3 + 13) × 6 ÷ 4
5: ((3 + 13) × 6) ÷ 4
6: (3 + 13) × (6 ÷ 4)
7: (13 + 3) ÷ 4 × 6
8: ((13 + 3) ÷ 4) × 6
9: (13 + 3) ÷ (4 ÷ 6)
10: (13 + 3) × 6 ÷ 4
11: ((13 + 3) × 6) ÷ 4
12: (13 + 3) × (6 ÷ 4)
13: (6 × (3 + 13)) ÷ 4
14: 6 × (3 + 13) ÷ 4
15: 6 × ((3 + 13) ÷ 4)
16: 6 ÷ 4 ×(3 + 13)
17: (6 ÷ 4) × (3 + 13)
18: 6 ÷ (4 ÷ (3 + 13))
19: 6 ÷ 4 ×(13 + 3)
20: (6 ÷ 4) × (13 + 3)
21: 6 ÷ (4 ÷ (13 + 3))
22: (6 × (13 + 3)) ÷ 4
23: 6 × (13 + 3) ÷ 4
24: 6 × ((13 + 3) ÷ 4)
25: 6 ÷ (13 ÷ 4 - 3)
26: 6 ÷ ((13 ÷ 4) - 3)
追问
能告诉我具体的方法吗?
追答
其实这没有什么方法。。就是每个数字都试一遍。像这个题目:题目中包含4,所以得用其他3个数去凑出6与它相乘。。加减乘除都试一遍
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