Question

若a-b=4,ab=1,求(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)的值

Answer 1

您好：

(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)
=-2ab+2a+3b-3ab-2b+2a-a-4b-ab
=-6ab+3a-3b
=-6ab+3(a-b)
=-6x1+3x12
=-6+36
=30

不明白，可以追问
如有帮助，记得采纳，谢谢
祝学习进步！

Answer 2

(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)
=-2ab+2a+3b-3ab-2b-2a-a-4b-ab
=-2ab-3ab-ab+2a+2a-a+3b-2b-4b
=-6ab-3a-3b
当a-b=4 ab=1原式
=-6ab-3a-3b
=-6+3a-3b
=-6+3(a-b)
=-6+3*4
=-6+12
=6
希望能够帮助你！
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Answer 3

原式=-2ab+2a+3b-3ab-2b+2a-a-4b-ab
=-6ab+3a-3b=-6ab+3(a-b)
代入=-6*1+3*4=6

Answer 4