
(2²+1)(2的四次方+1)(2的八次方+1)(2的16次方+1)
2个回答
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(2²+1)(2^4+1)(2^8+1)(2^16+1)
=(2²-1)(2²+1)(2^4+1)(2^8+1)(2^16+1)/(2²-1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)/3
=(2^8-1)(2^8+1)(2^16+1)/3
=(2^16-1)(2^16+1)/3
=(2^32-1)/3
=(2²-1)(2²+1)(2^4+1)(2^8+1)(2^16+1)/(2²-1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)/3
=(2^8-1)(2^8+1)(2^16+1)/3
=(2^16-1)(2^16+1)/3
=(2^32-1)/3
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