Question

先化简,再求值:(x+1)分之(x的平方-x)×(x的平方-2x+1)分之(x的平方-1)×(x-3),其中x满足x的平方-3x+2=0.

急啊，谢谢各位了

Answer 1

(x²-x)/(x+1)·(x²-1)/(x²-2x+1)·(x-3)
=[x(x-1)(x+1)(x-1)(x-3)]/[(x+1)(x-1)²
=x(x-3)
=x²-3x
∵x²-3x+2=0
∴x²-3x=-2
∴原式=-2