Question

(x-1)^2-x-1因式分解

还有1：4(x-y)^2-2(y-x)^3
x^2-3xy-10y^2
4x^2-4xy+y^2-z^2
(x^2+3x)^2-2(x^2+3x)-8

Answer 1

(x-1)^2-x-1

=x^2-2x+1-x-1
=x^2-3x
=x(x-3)
4(x-y)^2-2(y-x)^3
=4(x-y)^2+2(x-y)^3
=2(x-y)^2(2+x-y)
x^2-3xy-10y^2
=(x-5y)(x+2y)
4x^2-4xy+y^2-z^2
=(2x-y)^2-z^2
=(2x-y+z)(2x-y-z)
(x^2+3x)^2-2(x^2+3x)-8
=(x^2+3x+2)(x^2+3x-4)
=(x+2)(x+1)(x-1)(x+4)