已知2的96次方减1可以被60到70之间的2个整数整除,这两个数是多少?
1个回答
展开全部
2^96-1=(2^48+1)(2^48-1)=(2^48+1)(2^24+1)(2^24-1)=
(2^48+1)(2^24+1)(2^12+1)(2^12-1)=
(2^48+1)(2^24+1)(2^12+1)(2^6+1)(2^6-1)=
(2^48+1)(2^24+1)(2^12+1)(2^6+1)(2^3+1)(2^3-1)=
(2^48+1)(2^24+1)(2^12+1)(2^6+1) 9 * 7=
(2^48+1)(2^24+1)(2^12+1) 65 * 63
是65 63
(2^48+1)(2^24+1)(2^12+1)(2^12-1)=
(2^48+1)(2^24+1)(2^12+1)(2^6+1)(2^6-1)=
(2^48+1)(2^24+1)(2^12+1)(2^6+1)(2^3+1)(2^3-1)=
(2^48+1)(2^24+1)(2^12+1)(2^6+1) 9 * 7=
(2^48+1)(2^24+1)(2^12+1) 65 * 63
是65 63
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
