x的平方-y的平方分之xy÷（x-y分之1-x+y分之1）
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xy/(x²-y²)÷[1/(x-y)-1/(x+y)]
=xy/[(x+y)(x-y)]÷(x+y-x+y)/[(x-y)(x+y)]
=xy/[(x+y)(x-y)]÷(2y)/[(x-y)(x+y)]
=xy/[(x+y)(x-y)]×[(x-y)(x+y)]/(2y)
=x/2
=xy/[(x+y)(x-y)]÷(x+y-x+y)/[(x-y)(x+y)]
=xy/[(x+y)(x-y)]÷(2y)/[(x-y)(x+y)]
=xy/[(x+y)(x-y)]×[(x-y)(x+y)]/(2y)
=x/2
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