Question

2m+2分之(m+1)²÷m+1分之1×(m+3)² 分之(m+3)(m-3)

Answer 1

(m+1)²/(2m+2)÷1/(m+1)×(m+3)(m-3)/(m+3)²
=(m+1)/2×(m+1)×(m-3)/(m+3)
=(m+1)²(m-3)/[2(m+3)]

追问

2m+2分之(m+1)²×m+1分之1×(m+3)² 分之(m+3)(m-3)

追答

(m+1)²/(2m+2)×1/(m+1)×(m+3)(m-3)/(m+3)²
=1/2×(m-3)/(m+3)
=1/2×[1-6/(m+3)]
=1/2-3/(m+3)

追问

1/2怎么得出的？

追答

(m+1)²/(2m+2)×1/(m+1)
=(m+1)²/[2(m+1)×(m+1)]
=1/2