根号下(7/2)^2+(1/2)^2与(根号24-根号1/2+2倍的根号2/3)-(根号1/8+根号6) 两道计算
1个回答
展开全部
根号下(7/2)^2+(1/2)^2
=根号下(49/4+1/4)
=根号下50/4
=根号下[(25/4)*2]
=根号下[(5/2)^2*2]
=(5/2)*根号下2
(根号24-根号1/2+2倍的根号2/3)-(根号1/8+根号6)
=根号(4*6)-根号(2/4)+2根号(6/9)-根号(2/16)-根号6
=2根号6-(根号2)/2+(2/3)*根号6-(根号2)/4-根号6
=(2+2/3-1)*根号6-(1/2+1/4)*根号2
=(5/3)*根号6-(3/4)*根号2
=根号下(49/4+1/4)
=根号下50/4
=根号下[(25/4)*2]
=根号下[(5/2)^2*2]
=(5/2)*根号下2
(根号24-根号1/2+2倍的根号2/3)-(根号1/8+根号6)
=根号(4*6)-根号(2/4)+2根号(6/9)-根号(2/16)-根号6
=2根号6-(根号2)/2+(2/3)*根号6-(根号2)/4-根号6
=(2+2/3-1)*根号6-(1/2+1/4)*根号2
=(5/3)*根号6-(3/4)*根号2
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询