![](https://iknow-base.cdn.bcebos.com/lxb/notice.png)
(a^2-1)(a^4+a^2+1) 因式分解
1个回答
2013-03-05 · 知道合伙人教育行家
关注
![](https://wyw-base.cdn.bcebos.com/pc-content/follow.gif)
展开全部
(a^2-1)(a^4+a^2+1)
=(a+1)(a-1)[(a^4+2a^2+1)-a^2] (前一因子用平方差分解,后一因子将 a^2 变为 2a^2-a^2)
=(a+1)(a-1)[(a^2+1)^2-a^2]
=(a+1)(a-1)(a^2+a+1)(a^2-a+1)
=(a+1)(a-1)[(a^4+2a^2+1)-a^2] (前一因子用平方差分解,后一因子将 a^2 变为 2a^2-a^2)
=(a+1)(a-1)[(a^2+1)^2-a^2]
=(a+1)(a-1)(a^2+a+1)(a^2-a+1)
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询