设a大于0,b大于0,1/a-1/b-1/a+b=0,求(b/a)^2-(a/b)^2
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您好:
1/a-1/b-1/a+b=0,
1/a-1/b=1/a+b
(b-a)/ab=1/(a+b)
(b-a)(a+b)/ab=1
(b²-a²)/ab=1
b/a-a/b=1
(b/a-a/b)²=1²
(b/a)²-2+(a/b)²=1
(b/a)²+2+(a/b)²=5
(b/a+a/b)²=5
b/a+a/b=±√5
(b/a)²-(a/b)²
=(b/a+a/b)(b/a-a/b)
=±√5x1
=±√5
不明白,可以追问
如有帮助,记得采纳,谢谢
祝学习进步!
1/a-1/b-1/a+b=0,
1/a-1/b=1/a+b
(b-a)/ab=1/(a+b)
(b-a)(a+b)/ab=1
(b²-a²)/ab=1
b/a-a/b=1
(b/a-a/b)²=1²
(b/a)²-2+(a/b)²=1
(b/a)²+2+(a/b)²=5
(b/a+a/b)²=5
b/a+a/b=±√5
(b/a)²-(a/b)²
=(b/a+a/b)(b/a-a/b)
=±√5x1
=±√5
不明白,可以追问
如有帮助,记得采纳,谢谢
祝学习进步!
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