Question

分式计算，求解！！！

第四题，画五角形的

Answer 1

【参考答案】

6、计算
（1）原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/(xy)]
=[xy/(x+y)]×[xy/(x+y)]
=1

2、原式=[(1/a)+(1/b)]²÷[(1/a + 1/b)(1/a - 1/b)]
=(1/a +1/b)÷(1/a - 1/b)
=[(a+b)/(ab)]÷[(b-a)/(ab)]
=[(a+b)/(ab)×[-ab/(a-b)]
=(-a-b)/(a-b)

3、原式=[3x²/(4y)]²×[2y/(3x)]+[x²/(2y²)]÷[2y²/x]
=(3/8)(x/y)+[x²/(2y²)]×[x/(2y²)]
=[3x/(8y)]+[x³/(4y^4)]
=(3xy³+2x³)/(8y^4)

4、原式=[(a+b)²/(a-b)²]×(2/3)[(a-b)/(a+b)]-[a²/(a+b)(a-b)]×(b/a)]
=(2/3)[(a+b)/(a-b)]-[ab/(a+b)(a-b)]
=[(2/3)(a+b)²/(a+b)(a-b)]-[ab/(a+b)(a-b)]
=[(2/3)a²+(2/3)b²-(1/3)ab]/[(a+b)(a-b)]

追问

呃，能清楚点吗，不知道怎么书写到本子上了

追答

过程就是这些，很详细了。其中，"/"是分数线

Answer 2

（1）解原式=（x+2y)/(x+t)*(xy)/(x+2y)*(xy)/(x+y)
=x^2y^2/(x+y)^2
(2)解原式=(a+b)^2/(ab)^2((ab)^2/(a+b)(b-a)
=a+b/b-a
(3)解原式=3x^3/8y+(x^3/4y^4)
=(3x^3y^3+2x^3)/8y^4
(4)j解原式=2(a+b)/3(a-b)-ab/((a+b)(a-b)
=(2a^2+4ab+2b^2-3ab)/3(a^2-b^2)
=(2a^2+ab+2b^2)/3(a^2-b^2)

追问

第一个x+t？