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3^(2m-4n+1)
=[(3^m)^2/(3^n)^4]*3
=[(3^m)^2/(9^n)^2]*3
=6^2/(2^2)*3
=(36/4)*3
=108/4
=27不懂的欢迎追问,如有帮助请采纳,谢谢!
=[(3^m)^2/(3^n)^4]*3
=[(3^m)^2/(9^n)^2]*3
=6^2/(2^2)*3
=(36/4)*3
=108/4
=27不懂的欢迎追问,如有帮助请采纳,谢谢!
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展开全部
3^(2m-4n+1)
=[(3^m)^2/(3^n)^4]*3
=[(3^m)^2/(9^n)^2]*3
=6^2/(2^2)*3
=(36/4)*3
=108/4
=27
=[(3^m)^2/(3^n)^4]*3
=[(3^m)^2/(9^n)^2]*3
=6^2/(2^2)*3
=(36/4)*3
=108/4
=27
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