Question

化简:(1)-(-a/b)^2*(-b^3/a)^3/(ab)^4 (2)(-2a^3b^3)*{-b^2/(-2a)^2}/(a^3b^2)^2

(3)m-m^2/m^2-1/m/m-1*(m+1/m-1)^2 （4）（e+1/e)^2-（e-1/e)^2 急，谢了

Answer 1

(1)-(-a/b)^2*(-b^3/a)^3/(ab)^4
=-a^2/b^2*(-b^9/a^3)/(a^4*b^4)
=b^3/a^5

(2)(-2a^3b^3)*{-b^2/(-2a)^2}/(a^3b^2)^2
=-2a^3b^3*(-b^2)/(4a^2)/(a^6*b^4)
=b/(2a^5)

(3)(m-m^2)/(m^2-1)/[m/(m-1)]*[(m+1)/(m-1)]^2
=m(1-m)/[(m-1)(m+1)]*(m-1)/m*(m+1)^2/(m-1)^2
=-(m+1)/(m-1)

(4)（e+1/e)^2-（e-1/e)^2

=e^2+2+1/e^2-(e^2-2+1/e^2)
=4