2的三分之四次方除以3的三分之二次方*6的三分之二次方 要过程!
展开全部
2^(3/4)/3^(2/3)*6^(2/3)
=2^(3/4)*3^(-2/3)*[2*3]^(2/3)
=2^(3/4)*3^(-2/3)*2^(2/3)*3^(2/3)
=2^(2/3)*2^(3/4)*3^(2/3)*3^(-2/3)
=2^(2/3+3/4)*3^(2/3-2/3)
=2^(17/12)*3^0
=2^(17/12)
=2^(3/4)*3^(-2/3)*[2*3]^(2/3)
=2^(3/4)*3^(-2/3)*2^(2/3)*3^(2/3)
=2^(2/3)*2^(3/4)*3^(2/3)*3^(-2/3)
=2^(2/3+3/4)*3^(2/3-2/3)
=2^(17/12)*3^0
=2^(17/12)
追问
可为什么用计算器算出来等于4
追答
2^(4/3)/3^(2/3)*6^(2/3)
==2^(4/3)*3^(-2/3)*[2*3]^(2/3)
=2^(4/3)*3^(-2/3)*2^(2/3)*3^(2/3)
=2^(2/3+4/3)*3^(2/3-2/3)
=2^2*3^0
=2^2
=4
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询