Question

解方程：（x²+4x+3）分之x -（x+3）分之2=1

解方程：（x²+4x+3）分之x -（x+3）分之2=1

Answer 1

赞同tllau38|十四级 正解：x=-4。如x=-1,分母就为0了，不成立。

Answer 2

x/(x^2+4x+3) - 2/(x+3) =1
x/[(x+3)(x+1)] - 2/(x+3) =1
x-2(x+1) = (x+3)(x+1)
-x-1=x^2+4x+3
x^2+5x+4=0
(x+1)(x+4) =0
x=-4 or -1(rej)
ie x=-4

Answer 3

x /（x²+4x+3） - 2 /（x+3）=1

x / [(x+3)(x+1)] - 2 / (x+3) =1
[ x-2(x+1)] / [(x+3)(x+1)] =1
(x-2x-1) =(x+3)(x+1)
(-x-1) = (x+3)(x+1)
-(x+1) = (x+3)(x+1)
-1 =x+3
x =-4
令x+1=0
x =-1

x=-1 or x=-4

Answer 4

x²+4x+3≠0, x+3≠0
x≠-1或-3

x/(x²+4x+3) - 2/(x+3) =1
[x- 2(x+1)]/(x²+4x+3)=1
-x-2=x²+4x+3
x²+5x+5=0

x=(-5±√5) /2

Answer 5

解方程：
（x²+4x+3）分之x -（x+3）分之2=1
x/[(x+3)(x+1)-2(x+1)/[(x+3)(x+1)=1
x-2x-2=(x+3)(x+1)
x^2+5x+5=0
(x+2.5)^2=1.25
x+2.5=土√1.25
x1=-2.5+√1.25 x2=-2.5-√1.25