x²-1分之3x+4-x-1分之2括号除以x²-2x+1分之x+2
1个回答
展开全部
[(3x+4)/(x²-1)-2/(x-1)]÷[(x+2)/(x²-2x+1)]
=(x+2)/(x²-1)×(x²-2x+1)/(x+2)
=(x+2)/[(x+1)(x-1)]×(x-1)²/(x+2)
=(x-1)/(x+1)
=(x+2)/(x²-1)×(x²-2x+1)/(x+2)
=(x+2)/[(x+1)(x-1)]×(x-1)²/(x+2)
=(x-1)/(x+1)
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
