Question

求解一道概率论题目

如图

Answer 1

P(A∪B)=P(A)+P(B)-P(AB)=5/8
P((A拔)B)=P(B)-P(AB)=3/8 (AB+(A拔)B=B)

P((B拔)A)=P(A)-P(AB)=1/8

(AB)拔=(A拔)∪(B拔), (A∪B)((AB)拔)=(A∪B)((A拔)∪(B拔))=A(B拔)+B(A拔)
P[(A拔)∪(B拔)]=P(A(B拔))+P(B(A拔))=1/2

Answer 2

P(A∪B)=P(A)+P(B)-P(AB)=1/4+1/2-1/8=5/8

P(A拔B)=P(B)-P(AB)=1/2-1/8=3/8

(A∪B)与(A拔B拔)是相互独立的
∴P[(A∪B)(A拔B拔)]=P(A∪B)×P(A拔B拔)=5/8×(1-5/8)=15/64

满意请采纳，谢谢~

Answer 3

P(A∪B)=P(A)+P(B)-P(AB)=1/4+1/2-1/8=5/8

P(非A B)=P(B)-P(AB)=1/2-1/8=3/8

P[(A∪B)(非AB)]=7/8 最后一题是说非AB 而不是非A非B