化简x²/(y-x)+y²/(x-y)的结果是
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原式=x²/(y-x)+(-y²)/[-(x-y)]
=x²/(y-x) - y²/(y-x)
=(x²- y²)/(y-x)
=(x-y)(x+y)/(y-x)
= -x-y
望君采纳,祝君学习进步~!~!~!
=x²/(y-x) - y²/(y-x)
=(x²- y²)/(y-x)
=(x-y)(x+y)/(y-x)
= -x-y
望君采纳,祝君学习进步~!~!~!
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原式=x²/(y-x)-y²/(y-x)
=(x²-y²)/(y-x)
=(x-y)(x+y)/(y-x)
=x+y
=(x²-y²)/(y-x)
=(x-y)(x+y)/(y-x)
=x+y
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= -x^2/(x-y)+y^2/(x-y)
=(y^2-x^2)/(x-y)
=-(y+x))(x-y)/(x-y)
=-(y+x)
=-y-x
=(y^2-x^2)/(x-y)
=-(y+x))(x-y)/(x-y)
=-(y+x)
=-y-x
追问
正解是-x-y,不过谢谢了
追答
-x-y和-y-x是一样的
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