【1/(x+y)^2-1/(x-y)^2】÷(1/x+y-1/x-y) 各位高手帮帮忙 急急急
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[1/(x+y)^2-1/(x-y)^2】÷(1/x+y-1/x-y)
=[(x-y^2-(x+y)^2]/(x+y)^2(x-y)^2÷[(x-y)-(x+y)]/(x+y)(x-y)
=-4xy/(x+y)^2(x-y)^2*(x+y)(x-y)/(-2y)
=2x/(x+y)(x-y)
=[(x-y^2-(x+y)^2]/(x+y)^2(x-y)^2÷[(x-y)-(x+y)]/(x+y)(x-y)
=-4xy/(x+y)^2(x-y)^2*(x+y)(x-y)/(-2y)
=2x/(x+y)(x-y)
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