
你会解方程x-1分之x - x-2分之x-1=x-4分之x-3 - x-5分之x-4吗?试试看。
1个回答
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原等式化简为
【1+1/(x-1)】-【1+1/(x-2)】=【1+1/(x-4)】【1+1/(x-5)】
1/(x-1)-1/(x-2)=1/(x-4)-1/(x-5)
[x-2-(x-1)]/(x-1)(x-2)=[x-5-(x-4)]/(x-4)(x-5)]
(x-1)(x-2)=(x-4)(x-5)
x²-3x+2=x²-9x+20
解得x=3
【1+1/(x-1)】-【1+1/(x-2)】=【1+1/(x-4)】【1+1/(x-5)】
1/(x-1)-1/(x-2)=1/(x-4)-1/(x-5)
[x-2-(x-1)]/(x-1)(x-2)=[x-5-(x-4)]/(x-4)(x-5)]
(x-1)(x-2)=(x-4)(x-5)
x²-3x+2=x²-9x+20
解得x=3
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