Question

已知数a,b,c满足下列条件:|a+1|+(b-2)^2+4(c^2)+4c+1=0,求[(abc)^25]÷[(a^11)(b^8)(c^7)]

Answer 1

4(c^2)+4c+1=（2c+1）^2>=0
(b-2)^2>=0
|a+1|>=0
因为:|a+1|+(b-2)^2+4(c^2)+4c+1=0
所以（2c+1）^2=0 c=-1/2
|a+1|=0 a=-1
(b-2)^2=0 b=2
abc=1
a^11=-1
bc=-1
(b^8)(c^7)=(bc)^7*b=-2
原式=1/2

Answer 2

a=-1 , b=2 , c=-1/2

所以[(abc)^25]÷[(a^11)(b^8)(c^7)]= 1/ (-1*2^8* 2^-7) =1/-2 = -1/2

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