Question

高等数学求导数问题！！！

求 y=(1+sinx)^x 的导数，求出导数后令x=兀,求结果！

Answer 1

y'=(1+sinx)^xln(1+sinx)(1+sinx)'=(1+sinx)^xln(1+sinx)cosx
x=π时
y'=-1

Answer 2

y'=x(1+sinx)^x-1 *cosx =-兀,

Answer 3

y'=(1+sinx)^(x-1)*cosx+(1+sinx)^xln(1+sinx)
y'(π)=-1+0=-1

Answer 4

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