Question

初二数学分式方程求解答过程！！

Answer 1

3(x-2)/(x-2)(x+3)=4(x+1)/(x-4)(x+1)
3/(x+3)=4/(x-4)
3(x-4)=4(x+3)
3x-12=4x+12
-x=24
x=-24
经检验，x=-24是原方程的根
所以，原方程的解为x=-24

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Answer 2

原式等于3(x-2)/(x-2)(x+3)=4(x+1)/(x+1)(x-4)
3/(x+3)=4/(x-4)
3(x-4)-4(x+3)=0
3x-12-4x-12=0
x=-24

Answer 3

3(x-2)/(x-2)(x+3)=4(x+1)/(x+1)(x-4)
3/x+3=4/x-4
3(x-4)=4(x+3)
3x-12=4x+12
x=-24

Answer 4

原式可化为：
[3(x-2)]/[(x 3)(x-2)]=[4(x 1)]/[(x 1)(x-4)]
整理得：3/(x 3)=4/(x-4)
3x-12=4x 12
x=-24

Answer 5

3(x-2)/(x 3)•(x-2)=4(x 1)/(x 1)•(x-4)
这样就约掉了(x-2)和(x 1)，然后就是
3/(x 3)=4/(x-4)
通分以后就是3x-12=4x 12所以x=-24

Answer 6

分式可以写成3（x-2）/[(x-2)(x-3)]=4(x+1)/[(x-4)(x+1)],分式化简得3/(x-3)=4/(x-4)最后结果，x=-24