运用平方差公式计算
(2x-1)(2x+1)(1/2a-2b)(1/2a+2b)(5m+3n)(3n-5m)(-x+y)(-x-y)101×999.8×10.2...
(2x-1)(2x+1)
(1/2a-2b)(1/2a+2b)
(5m+3n)(3n-5m)
(-x+y)(-x-y)
101×99
9.8×10.2 展开
(1/2a-2b)(1/2a+2b)
(5m+3n)(3n-5m)
(-x+y)(-x-y)
101×99
9.8×10.2 展开
1个回答
展开全部
(2x-1)(2x+1)
=(2x)²-1
=4x²-1
(1/2a-2b)(1/2a+2b)
=(1/2a)²-(2b)²
=1/4a²-4b²
(5m+3n)(3n-5m)
=(3n)²-(5m)²
=9n²-25m²
(-x+y)(-x-y)
=(-x)²-y²
=x²-y²
101×99
=(100+1)×(100-1)
=100²-1
=10000-1
=9999
9.8×10.2
=(10-0.2)×(10+0.2)
=10²-0.2²
=100-0.04
=99.96
=(2x)²-1
=4x²-1
(1/2a-2b)(1/2a+2b)
=(1/2a)²-(2b)²
=1/4a²-4b²
(5m+3n)(3n-5m)
=(3n)²-(5m)²
=9n²-25m²
(-x+y)(-x-y)
=(-x)²-y²
=x²-y²
101×99
=(100+1)×(100-1)
=100²-1
=10000-1
=9999
9.8×10.2
=(10-0.2)×(10+0.2)
=10²-0.2²
=100-0.04
=99.96
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
