Question

高一数学题.急!!!!!!!!!!!!

化简（Asinα+Bcosα)的平方+（Acosα+Bsinα)的平方
要过程啊！

Answer 1

=(Asinα)^2+(Bcosα)^2+2ABsinαcosα+(Acosα)^2+(Bsinα)^2+2ABsinαcosα
=A^2+B^2+8ABsin2α
嫌过程少么？

Answer 2

（Asina+Bcosa)^2+（Acosa+Bsina)^2
=A^2sin^2a+2ABsinacosa+B^2cos^2a+A^2cos^2a+2ABsinacosa+B^2sin^2a
=A^2(sin^2a+cos^2a)+B^2(sin^2a+cos^2a)+4ABsinacosa
=A^2+B^2+2ABsin(2a)