Question

oracle sql报表统计，怎么按订单类别，分组显示订单总数和交易成功订单数。

输出格式为 ：
订单类型 订单总数 交易成功订单总数
A 10 5
B 20 8

Answer 1

SELECT
ord.ORDER_TYPE as 订单类型,
COUNT(ord.ORDER_ID) as 订单总数,
orde.succCount as 交易成功订单总数
FROM
ORDER ord
LEFT JOIN
(
SELECT
ORDER_TYPE,
COUNT(ORDER_ID) AS succCount
FROM
ORDER
WHERE
STATUS_ID = 'ORDER_SUCCESS'
GROUP BY
ORDER_TYPE
)
orde
ON
orde.ORDER_TYPE = ord.ORDER_TYPE
GROUP BY
ord.ORDER_TYPE;

还有一种方法是，

SELECT
ORDER_TYPE AS 订单类型,
STATUS_ID AS 订单状态,
COUNT(ORDER_ID) AS 订单数
FROM
ORDER
GROUP BY
ORDER_TYPE,
STATUS_ID;
查出以订单类型的不同状态为分组的订单数，然后在代码中求订单总数

Answer 2

select
订单类型,sum(订单数),sum(交易成功订单数) from table_name group by 订单类型

Answer 3

表order 类型type 总数sum 交易成功数amount

select type,count(sum),count(amount) from order group by type;

Answer 4

select a.订单类型, sum(a.交易成功订单总数) from table a group by a.订单类型