Question

请问怎样化简（x+1/2)^2+(x-1/2)^2+(x+1/2)(x-1/2) 谢谢

Answer 1

（x+1/2)^2+(x-1/2)^2+(x+1/2)(x-1/2)

=（x+1/2)^2+(x-1/2)^2+2(x+1/2)(x-1/2)-(x+1/2)(x-1/2)
=[（x+1/2)+（x-1/2)]²-(x+1/2)(x-1/2)
=(2x)²-(x²-1/4)
=4x²-x²+1/4
=3x²+1/4

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Answer 2

全部拆开也不麻烦啊，或者稍微简单一步，就是把2个平方项的其中一项跟最后一项，提取相同项，这样也就方便一点点，如果跟你问的意思有出入的话，请继续补充

Answer 3

（x+1/2)^2+(x-1/2)^2+(x+1/2)(x-1/2)
=x^2+x+1/4+x^2-x+1/4+x^2-1/4
=3x^2+1/4

追问

从=x^2+x+1/4+x^2-x+1/4+x^2-1/4开始 详细点

追答

（x^2+x^2+x^2）+（x-x）+(1/4+1/4-14/）=3x^2+1/4

Answer 4

((x+1/2)+(x-1/2))^2