分解因式①(x²+y²)²-4x²y² ②4x²-(x²+1)²
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①(x²+y²)²-4x²y²
=(x²+y²+2xy)(x²+y²-2xy)
=(x+y)²(x-y)²
②4x²-(x²+1)²
=(2x+x²+1)(2x-x²-1)
=-(x+1)²(x-1)²
=(x²+y²+2xy)(x²+y²-2xy)
=(x+y)²(x-y)²
②4x²-(x²+1)²
=(2x+x²+1)(2x-x²-1)
=-(x+1)²(x-1)²
追问
不能再往下算了吗?
追答
嗯,不能。
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①(x²+y²)²-4x²y²
=(x²+2xy+y²)(x²-2xy+y²)
=(x+y)²(x-y)²
②4x²-(x²+1)²
=-[(x²+2x+1)(x²-2x+1)]
=-(x+1)²(x-1)²
=(x²+2xy+y²)(x²-2xy+y²)
=(x+y)²(x-y)²
②4x²-(x²+1)²
=-[(x²+2x+1)(x²-2x+1)]
=-(x+1)²(x-1)²
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①(x²+y²)²-4x²y²
=(x²+y²+2xy)(x²+y²-2xy(
=(x+y)²)(x-y)²
②4x²-(x²+1)²
=(2x-x²-1)(2x+x²+1)
=-(x²-2x+1)(x²+2x+1)
=-(x-1)²(x+1)²
=(x²+y²+2xy)(x²+y²-2xy(
=(x+y)²)(x-y)²
②4x²-(x²+1)²
=(2x-x²-1)(2x+x²+1)
=-(x²-2x+1)(x²+2x+1)
=-(x-1)²(x+1)²
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①:(x^2+y^2)^2-4x^2y^2=x^4+2x^2y^2+y^4-4x^2y^2=x^4-2x^2y^2+y^4=(x^2-y^2)^2
②: 4x^2-(x^2+1)^2=4x^2-(x^4+2x^2+1)=-x^4+2x^2-1=-(x^2-1)^2
②: 4x^2-(x^2+1)^2=4x^2-(x^4+2x^2+1)=-x^4+2x^2-1=-(x^2-1)^2
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[X2 + Y2] 2-4x2y2
=(X2 + Y2 +2 XY),(X2 + Y2-2XY)
=(X + Y)2(XY) 2
=(X2 + Y2 +2 XY),(X2 + Y2-2XY)
=(X + Y)2(XY) 2
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