1-a-1/a/（a/a+2-1/a的平方+2a
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1-(a-1)/a÷[a/(a+2)-1/(a²+2a)]
=1-(a-1)/a÷[a/(a+2)-1/a(a+2)]
=1-(a-1)/a÷[(a²-1)/a(a+2)]
=1-(a-1)/a×a(a+2)/(a²-1)
=1-(a+2)/(a+1)
=-1/(a+1)
=1-(a-1)/a÷[a/(a+2)-1/a(a+2)]
=1-(a-1)/a÷[(a²-1)/a(a+2)]
=1-(a-1)/a×a(a+2)/(a²-1)
=1-(a+2)/(a+1)
=-1/(a+1)
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展开全部
1-(a-1)/a÷[a/(a+2)-1/(a²+2a)]
=1-(a-1)/a÷[a/(a+2)-1/a(a+2)]
=1-(a-1)/a÷[(a²-1)/a(a+2)]
=1-(a-1)/a×a(a+2)/(a²-1)
=1-(a+2)/(a+1)
=-1/(a+1)
=1-(a-1)/a÷[a/(a+2)-1/a(a+2)]
=1-(a-1)/a÷[(a²-1)/a(a+2)]
=1-(a-1)/a×a(a+2)/(a²-1)
=1-(a+2)/(a+1)
=-1/(a+1)
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