Question

计算一块砖的质量为0.3kg,长宽厚为24,12,6把它分别平放,侧放....对地面的压强

Answer 1

平放时：s=0.24*0.12=0.0288m^2
p=F/S=G/S=0.3*10/0.0288=104Pa；
侧放时：s=0.24*0.06=0.0144m^2
p=F/S=G/S=0.3*10/0.0144=208Pa；
立放时：s=0.12*0.06=0.0072m^2
p=F/S=G/S=0.3*10/0.0072=417Pa；

Answer 2

平放时：s=0.24*0.12=0.0288m^2
p=F/S=G/S=0.3*9.8/0.0288=101.92Pa；
侧放时：s=0.24*0.06=0.0144m^2
p=F/S=G/S=0.3*9.8/0.0144=203.84Pa；
立放时：s=0.12*0.06=0.0072m^2
p=F/S=G/S=0.3*9.8/0.0072=408.66Pa