Question

①6/根号2-根号18-（1/2)0次方-3的平方+根号（-2）的平方 ②根号12/6-6/根号18+1/根号3-根号2乘以根号6

③2b的平方/a+b -b+a ④a平方-2a+1/a-1 +a平方+a/a+1 ⑤(根号2+1)(根号2-1)-根号2(根号2+3)-(1-根号2)平方

Answer 1

6/√2-√18-(1/2)^0-3^2+√(-2)^2
=6*√2/2-3√2-1-9+2
=3√2-3√2-8
=-8

(√12)/6-6/√18+1/√3-√2*√6

=2√3/6-6*√18/18+√3/3-2√3
=√3/3-√18/3+√3/3-2√3
=-3√2/3-2√3+2√3/3
=-√2-4√3/3

2b的平方/(a+b -b+a)=2b^2/2a=b^2/a

a平方-2a+1/a-1 +a平方+a/a+1

=(a-1)^2/(a-1)+a(a+1)/(a+1)
=(a-1)+a
=2a-1

(根号2+1)(根号2-1)-根号2(根号2+3)-(1-根号2)平方

=(2-1)-(2+3√2)-(1+2-2√2)
=1-2-3√2-3+2√2
=-√2-4