Question

极坐标psin(&+派/4) =根号2/2怎么化成直角坐标方程，

Answer 1

解psin(&+派/4) =根号2/帆迅衡2
为昌拿psin(θ+π/态做4) =根号2/2
即psinθcosπ/4+pcosθsinπ/4=√2/2
由pcosθ=x，psinθ=y
即y*√2/2+x*√2/2=√2/2
即得到直线方程x+y=1

Answer 2

psin(&+派/4)
p(sin&cos派/4+cos&sin派/4)=√2/2
psin&*√2/2+pcos&*√2/2=√洞型2/2
psin&+pcos&=1
∵春颤咐pcos&=x psin&=y
∴扒纯x+y=1

Answer 3

极座标方程为psin(&+兀/4)=根号2/兆首2
化成直角坐标方程为：
psin&cos(π/4)+pcos&sin(π/4)=根号2/2,
则族改数y+x=1

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Answer 4

psin(&+派/4) =根号2/毁帆肢2
p（sin&cosπ/4＋cos&sinπ/4）=根号纤世2/2
y×根号2/2＋x×根号轿型2/2=根号2/2
所以
y＋x=1

Answer 5

极银滑座标方程亮知为psin(&+兀/4)=根号2/2
化成直角坐标方敬搏消程为：
psin&cos(π/4)+pcos&sin(π/4)=根号2/2,
则y+x=1