9(m+n)²-16(m-n)²
16a的4次方-72a²b²+81b4次方(x+y)²+10(x+y)+254a²b²-(a²+b)²...
16a的4次方-72a²b²+81b4次方 (x+y)²+10(x+y)+25 4a²b²-(a²+b)² (x+p)²-(x+q)² 3x的6次方-3x²
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干什么?因式分解吗?
如果是的话:
解1:
9(m+n)²-16(m-n)²
=[3(m+n)]²-[4(m-n)]²
=[3(m+n)-4(m-n)][3(m+n)+4(m-n)]
=(-m+7n)(7m-n)
=(7n-m)(7m-n)
解2:
16a的4次方-72a²b²+81b4次方
=16a^4-72a²b²+81b^4
=(4a²)²-2×4×9×a²b²+(9b²)²
=(4a²-9b²)²
=[(2a)²-(3b)²]²
=[(2a+3b)(2a-3b)]²
=(2a+3b)²(2a-3b)²
解3:
(x+y)²+10(x+y)+25
=(x+y)²+2×5×(x+y)+5²
=(x+y+5)²
解4:
4a²b²-(a²+b)²
=(2ab)²-(a²+b)²
=(2ab-a²-b)(2ab+a²+b)
=-(a²-2ab+b)(a²+2ab+b)
解5:
(x+p)²-(x+q)²
=(x+p+x+q)(x+p-x-q)
=(2x+p+q)(p-q)
解6:
3x^6-3x²
=3x²(x^4-1)
=3x²(x²-1)(x²+1)
=3x²(x-1)(x+1)(x²+1)
如果是的话:
解1:
9(m+n)²-16(m-n)²
=[3(m+n)]²-[4(m-n)]²
=[3(m+n)-4(m-n)][3(m+n)+4(m-n)]
=(-m+7n)(7m-n)
=(7n-m)(7m-n)
解2:
16a的4次方-72a²b²+81b4次方
=16a^4-72a²b²+81b^4
=(4a²)²-2×4×9×a²b²+(9b²)²
=(4a²-9b²)²
=[(2a)²-(3b)²]²
=[(2a+3b)(2a-3b)]²
=(2a+3b)²(2a-3b)²
解3:
(x+y)²+10(x+y)+25
=(x+y)²+2×5×(x+y)+5²
=(x+y+5)²
解4:
4a²b²-(a²+b)²
=(2ab)²-(a²+b)²
=(2ab-a²-b)(2ab+a²+b)
=-(a²-2ab+b)(a²+2ab+b)
解5:
(x+p)²-(x+q)²
=(x+p+x+q)(x+p-x-q)
=(2x+p+q)(p-q)
解6:
3x^6-3x²
=3x²(x^4-1)
=3x²(x²-1)(x²+1)
=3x²(x-1)(x+1)(x²+1)
追问
是不是 很懂这个 能加下QQ吗 方便教下
追答
抱歉,本人没有QQ。
再说了,仅凭悬赏分,是请不到家教的。
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