Question

(4a²-b)²-(4a²+b)²等于多少？（过程要详细）

Answer 1

(4a²-b)²-(4a²+b)²

=[(4a²-b)+(4a²+b)][(4a²-b)-(4a²+b)]

=8a²*(-2b)

=-16a²b

运用a²-b²=（a+b）（a-b）

Answer 2

(4a²-b)²-(4a²+b)²
=16a^4-8a²b+b²-(16a^4+8a²b+b²)
=16a^4-8a²b+b²-16a^4-8a²b-b²
=-16a²b