Question

先化简代数式(a+1/a-1+1/a^2-2a+1)/a/a-1,然后选取一个使原式有意义的a值代入求值

Answer 1

(a+1/a-1+1/a方-2a+1)/(a/a-1)
=[(a�0�5-1)/(a-1)�0�5+1/(a-1)�0�5]*(a-1)/a
=[a�0�5/(a-1)�0�5)]*(a-1)/a
=a/(a-1)
当a=2时,原式=2/(2-1)=2

Answer 2

(a+1/a-1+1/a²-2a+1)/(a/a-1)
=[(a²-1)/(a-1)²+1/(a-1)²]*(a-1)/a
=[a²/(a-1)²)]*(a-1)/a
=a/(a-1)
当a=2时,原式=2/(2-1)=2

Answer 3

抱歉！原题题意不明确（分子分母未用括号区别，无法确认运算顺序），无法直接解答。

请审核原题，追问时补充完整，谢谢！

Answer 4

原式=[(a+1)/(a-1)+1/(a-1)^2]÷a/(a-1)
=a^2/(a-1)^2*(a-1)/a
=a/(a-1)
令a=2，
原式=2/(2-1)=2。