Question

C++中如何从系统获取时间,并将其赋给一个string类型,如何办到?形式是类似于2013.03.31类型的就行了!

Answer 1

#include <Windows.h>
#include <Stdio.h>
void main()
{
SYSTEMTIME st;
GetLocalTime(&st);
char strTime[20];
sprintf("%d.%d.%d",st.wYear,st.wMonth,st.wDay);
printf(strTime);
}

以上代码直接显示, strTime 就是你说的 2013.3.31 的效果

Answer 2

#include <iostream>
#include <fstream>
using namespace std;
int main(){
string str;
//string str = "chenchen";
//ofstream fout("readstring.dat");
//fout.write((char*)(str.c_str()),str.size());
// fout.close();
ifstream fin("readstring.dat");
fin.read((char*)str.c_str(),str.size());
cout<<"str:"<<str<<endl;
fin.close();
cout<<"read over!"<<endl;
return 0;
}

Answer 3

#include <windows.h>
#include <stdio.h>
#include <stdlib.h>
int main()
{
SYSTEMTIME sTime;
GetSystemTime(&sTime);
printf("系统时间是：%d.%d.%d %d:%d:%d\n",sTime.wYear,sTime.wMonth,sTime.wDay,sTime.wHour,sTime.wMinute,sTime.wSecond);
system("pause");
return 0;
}

Answer 4

time_t t ;
t = time(NULL);
tm * pt = localtime(&t);
char buf[7]={0};
strftime(buf,sizeof(buf),"%y%m%d",pt);
strint str(buf);