Question

java计算编程x^n(x的n次方)的递归方法

写好一点，万分感谢！

Answer 1

晕`~
public long power(int x, int n)

{ if(1==n)
{ return x; }
else{ return x*power(x, n-1);
}
}
public static void main(String[] args)
{
int num1 = Integer.parseInt(args[0]);
int num2 = Integer.parseInt(args[1]);
Recursion r = new Recursion();
System.out.println(r.power(num1 ,num2)); }

Answer 2

class Recursion
{
public long power(int x, int n)
{
if(1==n){
return x;
}else{
return x*power(x, n-1);
}
}

public static void main(String[] args)
{
Recursion r = new Recursion();
System.out.println(r.power(2,3));
}
}
你试试吧！