Question

计算或化简谢谢！求过程

计算或化简
1.根号3cos30°+根号2sin45°
2.sin60°分之tan45°-cos60°×tan30°
3（sin60°+cos45°）（sin60°-cos45°） 谢谢

Answer 1

1.根号3cos30°+根号2sin45°
=√3*√3/2+√2*√2/2
=3/2+1
=5/2

2.sin60°分之tan45°-cos60°×tan30°
=1/(√3/2)-1/2*√3/3
=2√3/3-√3/6
=√3/2

3（sin60°+cos45°）（sin60°-cos45°）
=sin²60°-cos²45°
=(√3/2)²-(√2/2)²
=3/4-2/4
=1/4

Answer 2

解：﹙1﹚原式＝3×√3/2＋√2×√2/2＝3√3/2＋1
﹙2﹚原式＝1/﹙√3/2﹚－1/2×√3/3＝√3/2
﹙3﹚原式＝﹙√3/2＋√2/2﹚×﹙√3/2－√2/2﹚＝1/4.

Answer 3

十七级正解，混任务，走人