Question

java中提取字符串中的数字

要求：1、可以提取间隔的数字且连续数字作为一个整体提取出来。2、用正则表达式实现。如：abc12jlskdf4a,提取结果为12,4.

Answer 1

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Arrays;

public class NumberSplit {

public StringBuffer getString(String str) {
StringBuffer strbuf = new StringBuffer("t");
boolean flag = true;
for (int i = 0; i < str.length(); i++) {
char c = str.charAt(i);
// 判断是否是数字
if (c >= '0'&& c <= '9') {
// 判断和字符串中的数字是否重复
for (int j = 1; j < strbuf.length(); j++) {
if (c == strbuf.charAt(j)) {
// 如果重复,标志位数值为false,并跳出循环;否则标志位设置为true.
flag = false;
break;
} else
flag = true;
}

// 只有在即是数字又不重复的情况下才将改字符拼接到字符串上.
if (flag) {
strbuf.append(c);
}
}
}
return strbuf;
}

public static void main(String args[]) throws Exception {
System.out.println("请输入一段字符串,并以回车结束");
BufferedReader buf = new BufferedReader(
new InputStreamReader(System.in));
String str = buf.readLine();
StringBuffer strbuf = new NumberSplit().getString(str);
// 将返回的StringBuffer转换为字符数组
char c[] = strbuf.deleteCharAt(0).toString().toCharArray();
// 对字符数组排序
Arrays.sort(c);
// 输出字符数组
for (int i = 0; i < strbuf.length(); i++) {
System.out.print(c[i]);
}

}

import java.io.BufferedReader;
import java.io.InputStreamReader; 

import java.util.Arrays;

public class NumberSplit {

public StringBuffer getString(String str) {
 StringBuffer strbuf = new StringBuffer("t");
 boolean flag = true;
 

for (int i = 0; i < str.length(); i++) {
  char c = str.charAt(i);
 

// 判断是否是数字
  if (c >= '0'&& c <= '9') {
   // 判断和字符串中的数字是否重复
   for (int j = 1; j < strbuf.length(); j++) {
    if (c == strbuf.charAt(j)) {
     // 如果重复,标志位数值为false,并跳出循环;否则标志位设置为true.
     

flag = false;
     break;
    } else
     flag = true;
   }

   // 只有在即是数字又不重复的情况下才将改字符拼接到字符串上.
   if (flag) {
    strbuf.append(c);
   }
  }
 }
 return strbuf;
}

public static void main(String args[]) throws Exception {
 System.out.println("请输入一段字符串,并以回车结束");
 BufferedReader buf = new BufferedReader(
   new InputStreamReader(System.in));
 String str = buf.readLine();
 

StringBuffer strbuf = new NumberSplit().getString(str);
 // 将返回的StringBuffer转换为字符数组
 char c[] = strbuf.deleteCharAt(0).toString().toCharArray();
 

// 对字符数组排序
 Arrays.sort(c);
 // 输出字符数组
 for (int i = 0; i < strbuf.length(); i++) {
  System.out.print(c[i]);
 }

}

Answer 2

import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class test
{

public static void main(String args[]){

String str="abc12jlskdf4a";

Pattern p = Pattern.compile("[0-9\\.]+");
Matcher m = p.matcher(str);

while(m.find()){
System.out.print(m.group()+",");
}
}
}

希望对你有帮助

Answer 3

String sss = "abc12jlskdf4a";
System.out.println(sss.replaceAll("\\D+", ""));

Answer 4

String str="abc12jlskdf4a";
String[] mstr=str.split("[A-Za-z]");
String outstr="";
for (String string : mstr) {
if(string.matches("\\d+")){
outstr+=string+",";
}
}
outstr=outstr.substring(0,outstr.length()-1);
System.out.println(outstr);
你可以测试下~~结果和你的一样