先化简,再求值:其中x=2(x^2-2x-3/x^2-1-x+1/x-1)÷x-3/x-1
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(x^2-2x-3/x^2-1-x+1/碧山x-1)÷x-3/x-1
=[(x-3)(x+1)/(x-1)(x+1)-(x+1)/(x-1)]×(x-1)/(x-3)
=[(x-3)/(x-1)-(x+1)/(x-1)×(x-1)/(x-3)
=-4/(x-1)×(x-1)/(x-3)
=-4/(x-3)
当咐念x=2时
原衡慧困式=-4/(2-3)=4
=[(x-3)(x+1)/(x-1)(x+1)-(x+1)/(x-1)]×(x-1)/(x-3)
=[(x-3)/(x-1)-(x+1)/(x-1)×(x-1)/(x-3)
=-4/(x-1)×(x-1)/(x-3)
=-4/(x-3)
当咐念x=2时
原衡慧困式=-4/(2-3)=4
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