Question

初二数学题求解。。。

13/X-4 - 10/x-3 = 4/x-5 - 1/X-1 求这个方程的解

Answer 1

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解：
[13(x-3)-10(x-4)]/(x-4)(x-3)=[4(x-1)-(x-5)]/(x-5)(x-1)
(13x-39-10x+40)/(x-4)(x-3)=(4x-4-x+5)/(x-5)(x-1)
(3x+1)/(x-4)(x-3)=(3x+1)/(x-5)(x-1)
(3x+1)(x-5)(x-1)=(3x+1)(x-4)(x-3)
(3x+1)(x-5)(x-1)-(3x+1)(x-4)(x-3)=0
(3x+1)(x²-6x+5-x²+7x-12)=0
(3x+1)(x-7)=0
∴x= -1/3 或 x=7

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Answer 2

[13(x-3)-10(x-4)]/(x-4)(x-3)=[4(x-1)-(x-5)]/(x-5)(x-1)
(3x+1)/(x-4)(x-3)=(3x+1)/(x-5)(x-1)
(3x+1)(x-5)(x-1)=(3x+1)(x-4)(x-3)
(3x+1)(x²-6x+5-x²+7x-12)=0
(3x+1)(x-7)=0
∴x=-1/3 或 x=7

就是这样啦

Answer 3

解：
[13(x-3)-10(x-4)]/(x-4)(x-3)=[4(x-1)-(x-5)]/(x-5)(x-1)
(13x-39-10x+40)/(x-4)(x-3)=(4x-4-x+5)/(x-5)(x-1)
(3x+1)/(x-4)(x-3)=(3x+1)/(x-5)(x-1)
(3x+1)(x-5)(x-1)=(3x+1)(x-4)(x-3)
(3x+1)(x-5)(x-1)-(3x+1)(x-4)(x-3)=0
(3x+1)(x²-6x+5-x²+7x-12)=0
(3x+1)(x-7)=0
∴x= -1/3 或 x=7

Answer 4

-1/3 or 7

Answer 5

x=-1/3 、 x=7