计算：(-2分之1a-4b+3)^2 2(a+1)^2-4(a+2)(a-2)+3(a-1)^2 (x+1)^2(x-1)^2(x^2+1)^2
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(-2分之1a-4b+3)^2
=(-a/2-4b)²+2(-a/2-4b)×3+9
=a²/4+4ab+16b²-3a-24b+9
2(a+1)^2-4(a+2)(a-2)+3(a-1)^2
=2(a²+2a+1)-4(a²-4)+3(a²-2a+1)
=2a²+4a+2-4a²+16+3a²-6a+3
=a²-2a+21
(x+1)^2(x-1)^2(x^2+1)^2
=[(x-1)(x+1)(x²+1)]²
=[(x²-1)(x²+1)]²
=(x^4-1)²
=x^8-2x^4+1
=(-a/2-4b)²+2(-a/2-4b)×3+9
=a²/4+4ab+16b²-3a-24b+9
2(a+1)^2-4(a+2)(a-2)+3(a-1)^2
=2(a²+2a+1)-4(a²-4)+3(a²-2a+1)
=2a²+4a+2-4a²+16+3a²-6a+3
=a²-2a+21
(x+1)^2(x-1)^2(x^2+1)^2
=[(x-1)(x+1)(x²+1)]²
=[(x²-1)(x²+1)]²
=(x^4-1)²
=x^8-2x^4+1
追问
麻烦再计算下 ：（2m+5)^2(2m-5)^2
追答
：（2m+5)^2(2m-5)^2
=[(2m+5)(2m-5)]²
=(4m²-25)²
=16m^4-200m²+625
请采纳，谢谢
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