(m-3除以3m的2次方-6m)除以(m+2-m-2分之5)怎样化简
3个回答
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是[m-3÷(3m²-6m)]÷[m+2-5/(m-2)]吗?
如果是的话:
解:
[m-3÷(3m²-6m)]÷[m+2-5/(m-2)]
={m-3/[3m(m-2)]}/[m+2-5/(m-2)]
={[m×3m(m-2)-3]/[3m(m-2)]}/{[(m+2)(m-2)-5]/(m-2)]}
={(3m³-6m²-3)/[3m(m-2)]}×[(m-2)/(m²-9)]
=(3m³-6m²-3)(m-2)/[3m(m-2)(m²-9)]
=(m³-2m²-1)/[m(m²-9)]
如果是的话:
解:
[m-3÷(3m²-6m)]÷[m+2-5/(m-2)]
={m-3/[3m(m-2)]}/[m+2-5/(m-2)]
={[m×3m(m-2)-3]/[3m(m-2)]}/{[(m+2)(m-2)-5]/(m-2)]}
={(3m³-6m²-3)/[3m(m-2)]}×[(m-2)/(m²-9)]
=(3m³-6m²-3)(m-2)/[3m(m-2)(m²-9)]
=(m³-2m²-1)/[m(m²-9)]
展开全部
(m-3除以3m的2次方-6m)除以(m+2-m-2分之5)
=(m-3)/(3m^2-6m)÷[m+2-5/(m-2)]
=(m-3)/3m(m-2)÷[(m+2)(m-2)-5]/(m-2)
=(m-3)/3m(m-2)÷[(m^2-4-5]/(m-2)
=(m-3)/(3m^2-6m)÷[m+2-5/(m-2)]
=(m-3)/3m(m-2)÷[(m+2)(m-2)-5]/(m-2)
=(m-3)/3m(m-2)÷[(m^2-4-5]/(m-2)
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