Question

LinearLayout无限添加View怎么报错啊！ linearLayout.addView(childLayout);这句运行第二次久报错

View layout = LayoutInflater.from(this).inflate(R.layout.brand_story_list, null);
int width = 94;
int height = _layout_story_init.getHeight();
View childLayout = LayoutInflater.from(BrandStoryActivity.this).inflate(R.layout.story_childlist, null);
_lv_listStory = (ListView) layout.findViewById(R.id.lv_story_brand);
LinearLayout linearLayout=(LinearLayout)layout.findViewById(R.id.layout_child_add);
_lv_listStory.setAdapter(new StroyListAdapter(list, this));
Map<String, Object> map=list.get(0);
int scop=1;
while (map!=null) {
scop++;
List<Map<String, Object>> listmap=(List<Map<String, Object>>) map.get("submenu");
linearLayout.addView(childLayout);
ListView lv_story_childlist=(ListView)layout.findViewById(R.id.lv_story_childlist);
lv_story_childlist.setAdapter(new StroyListAdapter(listmap, BrandStoryActivity.this));
map=listmap.get(0);

Answer 1

linearLayout.addView(childLayout);无法重复add的.

childLayout add之后它就有parent了.
要想重新添加就得再
childLayout = LayoutInflater.from(BrandStoryActivity.this).inflate(R.layout.story_childlist, null);

一下

Answer 2

简而言之：view的存在必须遵循“一个儿子只能有一个父亲”的原则！