Question

JS 时间相减得出天数

需要完整代码

Answer 1

// 给日期类对象添加日期差方法，返回日期与diff参数日期的时间差，单位为天
Date.prototype.diff = function(date){
  return (this.getTime() - date.getTime())/(24 * 60 * 60 * 1000);
}
// 构造两个日期，分别是系统时间和2013/04/08 12:43:45
var now = new Date();
var date = new Date('2013/04/08 12:43:45');
// 调用日期差方法，求得参数日期与系统时间相差的天数
var diff = now.diff(date);
// 打印日期差
alert(diff);

Answer 2

function isLeapYear(year) {
if (year % 4 == 0 && ((year % 100 != 0) || (year % 400 == 0))) {
return true;
}
return false;
}
function validatePeriod(fyear, fmonth, fday, byear, bmonth, bday) {
if (fyear < byear) {
return true;
} else if (fyear == byear) {
if (fmonth < bmonth) {
return true;
} else if (fmonth == bmonth) {
if (fday <= bday) {
return true;
} else {
return false;
}
} else {
return false;
}
} else {
return false;
}
}
function dateDiff(d1, d2) {
var disNum = compareDate(d1, d2);
return disNum;
}
function compareDate(date1, date2) {
var regexp = /^(\d{1,4})[-|\.]{1}(\d{1,2})[-|\.]{1}(\d{1,2})$/;
var monthDays = [0, 3, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1];
regexp.test(date1);
var date1Year = RegExp.$1;
var date1Month = RegExp.$2;
var date1Day = RegExp.$3;

regexp.test(date2);
var date2Year = RegExp.$1;
var date2Month = RegExp.$2;
var date2Day = RegExp.$3;

if (validatePeriod(date1Year, date1Month, date1Day, date2Year, date2Month, date2Day)) {
firstDate = new Date(date1Year, date1Month, date1Day);
secondDate = new Date(date2Year, date2Month, date2Day);

result = Math.floor((secondDate.getTime() - firstDate.getTime()) / (1000 * 3600 * 24));
for (j = date1Year; j <= date2Year; j++) {
if (isLeapYear(j)) {
monthDays[1] = 2;
} else {
monthDays[1] = 3;
}
for (i = date1Month - 1; i < date2Month; i++) {
result = result - monthDays[i];
}
}
return result;
}
return;
}
days = dateDiff('2013-04-08', '2013-04-9') + 1;