Question

（x^2+y^2)^2-4xy(x^2+y^2)+4x^2y^2 1/2a^3x^2-2a^2xy+2ay^2 因式分解

（x^2+y^2)^2-4xy(x^2+y^2)+4x^2y^2
1/2a^3x^2-2a^2xy+2ay^2
因式分解

Answer 1

（x^2+y^2)^2-4xy(x^2+y^2)+4x^2y^2
=(x²+y²-2xy)²
=(x-y)^4

1/2a^3x^2-2a^2xy+2ay^2
=1/2a(a²x²-4axy+4y²)
=1/2a(ax-2y)²

追问

(x^2-2x)^2-6(x^2-2x)+9会么

追答

(x^2-2x)^2-6(x^2-2x)+9
=(x²-2x+3)
=(x+1)(x-3)